\(\sqrt{\left(4-\sqrt{5}\right)^2}-\sqrt{6-2\sqrt{5}}\)
\(=\sqrt{\left(4-\sqrt{5}\right)^2}-\sqrt{5-2\sqrt{5}+1}=\sqrt{\left(4-\sqrt{5}\right)^2}\)
\(=\sqrt{\left(\sqrt{5-1}^2\right)}\)
\(=|4-\sqrt{5}|-|\sqrt{5}-1|\)
\(=4-\sqrt{5}-\sqrt{5}+1=5-2\sqrt{5}\)
P/s: Khôg chắc lắm ạ
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`\sqrt{(4-\sqrt{5})^2}-\sqrt{6-2\sqrt{5}}`
`=|4-\sqrt{5}|-\sqrt{5-2\sqrt{5}+1}`
`=4-\sqrt{5}-\sqrt{(\sqrt{5}-1)^2}` (Vì `4 > \sqrt{5}`)
`=4-\sqrt{5}-|\sqrt{5}-1|`
`=4-\sqrt{5}-(\sqrt{5}-1)` (Vì `\sqrt{5} > 1`)
`=4-\sqrt{5}-\sqrt{5}+1=5-2\sqrt{5}`
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