A5

giúp mình nha khẩn cấp

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NM
27 tháng 10 2021 lúc 12:20

\(a,=\left(\dfrac{17}{14}-\dfrac{5}{7}\right)+\left(\dfrac{4}{9}-\dfrac{17}{18}\right)+\dfrac{11}{125}=\dfrac{1}{2}-\dfrac{1}{2}+\dfrac{11}{125}=\dfrac{11}{125}\\ b,=\left(\dfrac{11}{24}+\dfrac{13}{24}\right)-\left(\dfrac{5}{41}+\dfrac{36}{41}\right)+\dfrac{1}{2}=1-1+\dfrac{1}{2}=\dfrac{1}{2}\\ c,=\left(-12\right)\left(-\dfrac{1}{12}\right)^2=\dfrac{12}{12^2}=\dfrac{1}{12}\\ d,=\left(\dfrac{9}{25}-36\right):\left(\dfrac{19}{5}+\dfrac{1}{5}\right)=-\dfrac{891}{25}:4=-\dfrac{891}{100}\\ e,\dfrac{17}{12}\cdot\left(\dfrac{1}{20}\right)^2=\dfrac{17}{12}\cdot\dfrac{1}{400}=\dfrac{17}{4800}\\ f,=\dfrac{3}{8}\left(19\dfrac{1}{3}-33\dfrac{1}{3}\right)+\dfrac{1}{4}=\dfrac{3}{8}\cdot\left(-14\dfrac{1}{3}\right)+\dfrac{1}{4}=\dfrac{3}{8}\cdot\dfrac{43}{3}+\dfrac{1}{4}=\dfrac{43}{8}+\dfrac{1}{4}=\dfrac{45}{8}\\ g,=\dfrac{5}{3}\left(-16\dfrac{2}{7}+28\dfrac{2}{7}\right)=\dfrac{5}{3}\cdot12\dfrac{2}{7}=\dfrac{5}{3}\cdot\dfrac{86}{7}=\dfrac{430}{21}\)

\(h,=\dfrac{7}{2}\left(-\dfrac{3}{4}+\dfrac{5}{13}-\dfrac{9}{4}-\dfrac{8}{13}\right)=\dfrac{7}{2}\left(-3-\dfrac{3}{13}\right)=\dfrac{7}{2}\left(-\dfrac{42}{13}\right)=-\dfrac{147}{13}\\ i,=9^2-25^2+8^2=81-625+64=-480\\ k,=\left(1-1\right)-\left(\dfrac{1}{2}+\dfrac{1}{2}\right)+\left(2-2\right)-\left(\dfrac{2}{3}+\dfrac{1}{3}\right)+\left(3-3\right)-\left(\dfrac{3}{4}-\dfrac{1}{4}\right)+4\\ =-1-1-1+4=1\)

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