Question

Giúp mình câu này với cảm ơn nhiều ạ

Answer 1

\(=\dfrac{\left(7-4\sqrt{3}\right).\left(\sqrt{3}+2\right)}{3-4}-\dfrac{\left(28-10\sqrt{3}\right).\left(5+\sqrt{3}\right)}{25-3}\)

\(=\dfrac{7\sqrt{3}+14-12-8\sqrt{3}}{-1}-\dfrac{140+28\sqrt{3}-50\sqrt{3}-30}{22}\)

= \(\sqrt{3}-2-\dfrac{110-22\sqrt{3}}{22}\)

= \(\sqrt{3}-2-\dfrac{22.\left(5-\sqrt{3}\right)}{22}\)

\(=\sqrt{3}-2-5+\sqrt{3}=2\sqrt{3}-7\)