Bài 2:
\(\dfrac{404\times25-303\times33}{702-352-148}\\ =\dfrac{4\times101\times25-3\times101\times33}{202}\\ =\dfrac{100\times101-99\times101}{202}\\ =\dfrac{101\times\left(100-99\right)}{202}\\ =\dfrac{101\times1}{202}\\ =\dfrac{101}{202}\\ =\dfrac{1}{2}\)