Bài 3:
\(n_{Al}=\dfrac{5,4}{27}=0,2\left(mol\right)\\ a.2Al+6HCl\rightarrow2AlCl_3+3H_2\\ 0,2..........0,6...........0,2..........0,3\left(mol\right)\\ V_{H_2\left(đktc\right)}=0,3.22,4=6,72\left(l\right)\\ b.m_{AlCl_3}=133,5.0,2=26,7\left(g\right)\\ c.V_{ddHCl}=\dfrac{0,6}{0,8}=0,75\left(l\right)\)
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