Question

giúp mik với

Answer 1

\(\sqrt{2-3x=4}\)
   2 - 3x = \(4^2\)
   3x = 2 - 16
   3x = -14
   x= -14 : 3= \(\dfrac{-14}{3}\)
 Vậy x -= \(\dfrac{-14}{3}\)

Answer 2

√ 2 − 3 x = 4

2 - 3x = 4 2

3x = 2 - 16

3x = -14

x=  − 14 /3 Vậy x -= − 14/ 3

Answer 3

\(\sqrt{2-3x}=4\)

\(\sqrt{2-3x}=2^2\)

\(\Rightarrow2-3x=2\)

           \(3x=2-2\)

           \(3x=0\)

           \(x=0\)