Question

giúp mik với

Answer 1

\(a,\dfrac{5}{18}-x=0+\dfrac{7}{24}=\dfrac{7}{24}\)

\(x=\dfrac{5}{18}-\dfrac{7}{24}\)

\(x=\dfrac{20}{72}-\dfrac{21}{72}\)

\(x=\dfrac{-1}{72}\)

 

\(b,\dfrac{1}{2}-x=\dfrac{2}{5}-6\)

\(\dfrac{1}{2}-x=\dfrac{2}{5}-\dfrac{30}{5}=\dfrac{-28}{5}\)

\(x=\dfrac{1}{2}+\dfrac{28}{5}\)

\(x=\dfrac{5}{10}+\dfrac{56}{10}\)

\(x=\dfrac{61}{10}\)

Answer 2

a)

\(\dfrac{5}{18}-x=\dfrac{7}{24}\)

\(x=\dfrac{5}{18}-\dfrac{7}{24}=-\dfrac{1}{72}\)

b)

\(\dfrac{1}{2}-x=-\dfrac{28}{5}\)

\(x=\dfrac{1}{2}-\left(-\dfrac{28}{5}\right)=\dfrac{61}{10}\)