Question

GIÚP EM Ý 2 VỚI Ạ

Answer 1

Với x >= 0 ; x khác 9 

\(B=\dfrac{x-3\sqrt{x}-x-6\sqrt{x}-9+x+11\sqrt{x}+6}{x-9}\)

\(=\dfrac{x+2\sqrt{x}-3}{x-9}=\dfrac{\left(\sqrt{x}+3\right)\left(\sqrt{x}-1\right)}{x-9}=\dfrac{\sqrt{x}-1}{\sqrt{x}-3}\)

\(\Rightarrow P=A:B=\dfrac{\sqrt{x}-1}{\sqrt{x}+3}:\dfrac{\sqrt{x}-1}{\sqrt{x}-3}=\dfrac{\sqrt{x}-3}{\sqrt{x}+3}\)