\(a,\sqrt{x^2+2x+1}-2x=1\\ \Leftrightarrow a,\left|x+1\right|=1+2x\left(x\ge-\dfrac{1}{2}\right)\\ \Leftrightarrow\left[{}\begin{matrix}x+1=1+2x\\x+1=-1-2x\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=0\left(tm\right)\\x=-\dfrac{2}{3}\left(ktm\right)\end{matrix}\right.\)
b,ĐKXĐ:\(x\ge-2\)
\(\sqrt{x^2-8x+16}=x+2\\ \Leftrightarrow\left|x-4\right|=x+2\\ \Leftrightarrow\left[{}\begin{matrix}x-4=x+2\\x-4=-x-2\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}6=0\left(vô.lí\right)\\x=1\left(tm\right)\end{matrix}\right.\)
\(a,PT\Leftrightarrow\left|x+1\right|=2x+1\\ \Leftrightarrow\left[{}\begin{matrix}x+1=2x+1\left(x\ge-1\right)\\-x-1=2x+1\left(x< -1\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\left(tm\right)\\x=-\dfrac{2}{3}\left(ktm\right)\end{matrix}\right.\Leftrightarrow x=0\\ b,PT\Leftrightarrow\left|x-4\right|=x+2\\ \Leftrightarrow\left[{}\begin{matrix}x-4=x+2\left(x\ge4\right)\\4-x=x+2\left(x< 4\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x\in\varnothing\\x=1\left(tm\right)\end{matrix}\right.\Leftrightarrow x=1\)
\(\sqrt{\left(x+1\right)}\)2-2x=1
*x+1 -2x=1
=> x=0
*x+1-2x=-1
=>-x=-2
=>x=2
