\(n_{Zn}=\dfrac{13}{65}=0.2\left(mol\right)\)
\(n_{HCl}=\dfrac{300\cdot7.3}{100\cdot36.5}=0.6\left(mol\right)\)
\(Zn+2HCl\rightarrow ZnCl_2+H_2\)
\(0.2.......0.4........0.2.......0.2\)
\(\Rightarrow HCldư\)
\(V_{H_2}=0.2\cdot22.4=4.48\left(l\right)\)
\(m_{HCl\left(pư\right)}=0.4\cdot36.5=14.6\left(g\right)\)
\(m_{HCl\left(dư\right)}=\left(0.6-0.4\right)\cdot36.5=7.3\left(g\right)\)
\(m_{ZnCl_2}=0.2\cdot136=27.2\left(g\right)\)
\(m_{\text{dung dịch sau phản ứng}}=13+300-0.2\cdot2=312.6\left(g\right)\)
\(C\%_{HCl\left(dư\right)}=\dfrac{7.3}{312.6}\cdot100\%=2.3\%\)
\(C\%_{ZnCl_2}=\dfrac{27.2}{312.6}\cdot100\%=8.7\%\)
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