Question

Giúp em câu 5 bài 1

Answer 1

Với 0 < m < 1 

\(=\sqrt{m}-\sqrt{\left(\sqrt{m}-1\right)^2}=\sqrt{m}-\left(1-\sqrt{m}\right)=\sqrt{m}-1+\sqrt{m}=2\sqrt{m}-1\)

Answer 2

\(5,=\sqrt{m}-\sqrt{\left(\sqrt{m}-1\right)^2}\\ =\sqrt{m}-\left|\sqrt{m}-1\right|\\ =\sqrt{m}-\sqrt{m}+1\\ =1\)

Answer 3

5) \(\sqrt{m}-\sqrt{m-2\sqrt{m}+1}\)

\(=\sqrt{m}-\sqrt{\sqrt{m^2}-2\sqrt{m}+1^2}\)

\(=\sqrt{m}-\sqrt{\left(\sqrt{m}-1\right)^2}\)

\(=\sqrt{m}-\left|\sqrt{m}-1\right|\)

\(=\sqrt{m}-\sqrt{m}+1\)

\(=1\)

 

Answer 4

\(5.\sqrt{m}-\sqrt{m-2\sqrt{m}+1}\left(0< m< 1\right)\)

\(=\sqrt{m}-\left|\sqrt{m}-1\right|\)

\(=\sqrt{m}-1+\sqrt{m}\)

\(=2\sqrt{m}-1\)