\(2x^4-13x^3+24x^2-13x+2=0\)
\(\Leftrightarrow2x^4-8x^3+2x^2-5x^3+20x^2-5x+2x^2-8x+2=0\)
\(\Leftrightarrow2x^2\left(x^2-4x+1\right)-5x\left(x^2-4x+1\right)+2\left(x^2-4x+1\right)=0\)
\(\Leftrightarrow2x^2\left(x^2-4x+1\right)-5x\left(x^2-4x+1\right)+2\left(x^2-4x+1\right)=0\)
\(\Leftrightarrow\left(2x^2-5x+2\right)\left(x^2-4x+1\right)=0\)
\(\Leftrightarrow\left(2x^2-x-4x+2\right)\left(x^2-4x+1\right)=0\)
\(\Leftrightarrow\left[x\left(2x-1\right)-2\left(2x-1\right)\right]\left(x^2-4x+1\right)=0\)
\(\Leftrightarrow\left(x-2\right)\left(2x-1\right)\left(x^2-4x+1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=2;x=\frac{1}{2}\\x=\frac{4\pm\sqrt{12}}{2}\end{cases}}\)
bạn có thể giair theo cacsh đối xứng đươcj ko cái mà chia cả 2 vế cho x2 rồi đặt ý làm phuền bạn