Question

Giair các phương trình sau:

Answer 1

`[x-2]/[x+1]-[3x]/[x-1]+6=0`     `ĐK: x \ne +-1`

`=>(x-1)(x-2)-3x(x+1)+6(x-1)(x+1)=0`

`<=>x^2-2x-x+2-3x^2-3x+6x^2-6=0`

`<=>4x^2-6x-4=0`

`<=>2x^2-3x-2=0`

`<=>2x^2-4x+x-2=0`

`<=>(x-2)(2x+1)=0`

`<=>[(x=2),(x=-1/2):}` (t/m)