\(\sqrt{x^2+2x+1}+\sqrt{x^2-6x+9}\)
\(=\sqrt{\left(x+1\right)^2}+\sqrt{\left(x-3\right)^2}\)
\(=\left|x+1\right|+\left|x-3\right|\)
\(=x+1+x-3\)
\(=2x-2\)
\(=2\left(x-1\right)\)
\(\sqrt{x^2+2x+1}+\sqrt{x^2-6x+9}\)
\(=\sqrt{\left(x+1\right)^2}+\sqrt{\left(x-3\right)^2}\)
\(=\left|x+1\right|+\left|x-3\right|\)
\(=x+1+x-3\)
\(=2x-2\)
\(=2\left(x-1\right)\)
Giải PT : \(\sqrt{x^2-6x+9}-\sqrt{x^2-2x+1}=\sqrt{x^2}\)
giai pt x2+6x+1=(2x+1)\(\sqrt{x^2+2x+3}\)
Giai pt :GIÚP MÌNH VỚI
\(\sqrt{2x+4}-2\sqrt{2-x}=\frac{6x-4}{\sqrt{x^2+4}}\)
1. Giải pt:
\(\sqrt{x^2-2x+1}-\sqrt{x^2-6x+9}=10\)
2. Giải pt:
\(\sqrt{x+2\sqrt{x-1}}=3\sqrt{x-1}-5\)
1. Giải pt:
\(\sqrt{x^2-4x+3}+\sqrt{x-1}=0\)0
2. Giải pt:
\(\sqrt{x^2-2x+1}-\sqrt{x^2-6x+9}=10\)
Giải các PT sau:
\(a,\sqrt{x-2\sqrt{x-1}}-\sqrt{x-1}=1\)
\(b,\sqrt{x+3-4\sqrt{x-1}}+\sqrt{x+8+6\sqrt{x-1}}=1\)
\(c,\sqrt{x+\sqrt{2x-1}}+\sqrt{x-\sqrt{2x-1}}=\sqrt{2}\)
\(d,\sqrt{x+\sqrt{6x-9}}+\sqrt{x-\sqrt{6x-9}}=\sqrt{6}\)
a) Giai PT \(x^2-2x-2\sqrt{2x+1}-2=0\)
b) Giai hệ phương trình \(\hept{\begin{cases}x^2+y^2=4z-5+2xy\\x^4+y^4=9z-5-4z^2-2x^2y^2\end{cases}}\)
MONG CÁC BẠN ZẢI NHANH ZÚP
giải pt
\(\sqrt{4x^2}=3\)
\(\sqrt{x^2-6x+9}=2\)
\(\sqrt{\left(2x-3\right)^2}=6\)
\(\sqrt{25x^2}=100\)
\(\left(x+1\right)\sqrt{3x+1}-5\sqrt{2x-1}+\sqrt{6x^2-x-1}=5x+5\)
Giaỉ pt. Nhanh giúp mình