Violympic toán 9
Các câu hỏi tương tự
giải hệ pt:
(1) \(\left\{{}\begin{matrix}x^2-3xy+2y^2=0\\3x+y=6\end{matrix}\right.\)
(2)\(\left\{{}\begin{matrix}\dfrac{x-1}{2x+1}-\dfrac{y-2}{y+2}=1\\\dfrac{3x-3}{2x+1}+\dfrac{2y-4}{y+2}=3\end{matrix}\right.\)
(3)\(\left\{{}\begin{matrix}2\left(x+y\right)+\sqrt{x+1}=4\\x+y-3\sqrt{x+1}=-5\end{matrix}\right.\)
Giải phương trình:
1, left(x+3right)left(3x^4+8x^2+12x+21right)5left(x^2+1right)^3
2, 3left(x^2+2x-1right)^2-2left(x^2+3x-1right)^2+5x^20
3, dfrac{x^2+x+1}{x+1}+dfrac{x^2+2x+2}{x+2}-dfrac{x^2+3x+3}{x+3}-dfrac{x^2+4x+4}{x+4}0
4, left(dfrac{x+6}{x-6}right)left(dfrac{x+4}{x-4}right)^2+left(dfrac{x-6}{x+6}right)left(dfrac{x+9}{x-9}right)^22.dfrac{x^2+36}{x^2-36}
Đọc tiếp
Giải phương trình:
1, \(\left(x+3\right)\left(3x^4+8x^2+12x+21\right)=5\left(x^2+1\right)^3\)
2, \(3\left(x^2+2x-1\right)^2-2\left(x^2+3x-1\right)^2+5x^2=0\)
3, \(\dfrac{x^2+x+1}{x+1}+\dfrac{x^2+2x+2}{x+2}-\dfrac{x^2+3x+3}{x+3}-\dfrac{x^2+4x+4}{x+4}=0\)
4, \(\left(\dfrac{x+6}{x-6}\right)\left(\dfrac{x+4}{x-4}\right)^2+\left(\dfrac{x-6}{x+6}\right)\left(\dfrac{x+9}{x-9}\right)^2=2.\dfrac{x^2+36}{x^2-36}\)
Giải phương trình: \(x^4+3x^2-\dfrac{1}{x^4}-\dfrac{3}{x^2}-2=0\)
H24
22 tháng 6 2021 lúc 16:37
Giải pt:
\(\sqrt{x+1+\sqrt{x+\dfrac{3}{4}}}+x=\dfrac{1}{2}\)
giải pt
\(\dfrac{1}{x^2-3x+2}-\dfrac{x-5}{2-x}=\dfrac{3}{10}\)
giải hệ pt sau:
\(\left\{{}\begin{matrix}\dfrac{14}{x-y+2}-\dfrac{10}{x+y-1}=9\\\dfrac{3}{x-y+2}+\dfrac{2}{x+y-1}=4\end{matrix}\right.\)
Giải PT này giùm mk nha : \(10\cdot\left(\dfrac{x-2}{x+1}\right)^2+\left(\dfrac{x+2}{x-1}\right)^2-11\cdot\left(\dfrac{x^2-4}{x^2-1}\right)=0\)
giải pt :
a) \(\sqrt{x-1}+\sqrt{x^3+x^2+x+1}=1+\sqrt{x^4-1}\)
b0 \(4\sqrt{x+1}=x^2-5x+14\)
c) \(2x+3\sqrt{4-5x}+\sqrt{x+2}=8\)
d) \(\dfrac{x^2+x}{\sqrt{x^2+x+1}}=\dfrac{2-x}{\sqrt{x-1}}\)
Giải PT: \(\sqrt{1-x}+\sqrt{x^2-3x+2}+\left(x-2\right).\sqrt{\dfrac{x-1}{x-2}}=3\)