Question

giải pt

 

\(\sqrt{x^2+3x+6}=x+3\)

Answer 1

\(\sqrt{x^2+3x+6}=x+3\Leftrightarrow x^2+3x+6=x^2+6x+9\left(x\ge-3\right)\Leftrightarrow-3x=3\left(x\ge-3\right)\Leftrightarrow x=-1\left(nhận\right)\)