\(\left|\left|x-2\right|+3\right|=5\)
\(\Leftrightarrow\left[{}\begin{matrix}\left|x-2\right|+3=5\\\left|x-2\right|+3=-5\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}\left|x-2\right|=2\\\left|x-2\right|=-8\left(loai\right)\end{matrix}\right.\)
Có: \(\left|x-2\right|=2\Leftrightarrow\left[{}\begin{matrix}x-2=2\\x-2=-2\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=0\end{matrix}\right.\)
Vậy...............
Ta có : $||x-2|+3|=5$
\(=>\left[{}\begin{matrix}\left|x-2\right|+3=5\\\left|x-2\right|+3=-5\end{matrix}\right.\)
\(=>\left[{}\begin{matrix}\left|x-2\right|=2\\\left|x-2\right|=-8\end{matrix}\right.\)
Vì $|x-2| \geq 0$ nên trường hợp 2 vô lý.
$=>|x-2|=2$
\(=>\left[{}\begin{matrix}x-2=2\\x-2=-2\end{matrix}\right.\)
\(=>\left[{}\begin{matrix}x=4\\x=0\end{matrix}\right.\)