Question

giải pt sau 3x(x+5)-(x+2)^2=2x^2+7

Answer 1

\(3x\left(x+5\right)-\left(x+2\right)^2=2x^2+7\)

\(\Leftrightarrow3x^2+15x-x^2-4x-4=2x^2+7\)

\(\Leftrightarrow3x^2-2x^2-x^2+15x-4x=7+4\)

\(\Leftrightarrow11x=11\)

\(\Leftrightarrow x=1\)

Answer 2

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Answer 3

3x(x + 5) - (x + 2)² = 2x² + 7

<=> 3x² + 15x - x² - 4x - 4 = 2x² + 7

<=> 2x² + 11x - 4 = 2x² + 7

<=> 2x² + 11x - 4 - 2x² = 7

<=> 11x - 4 = 7

<=> 11x = 7 + 4

<=> 11x = 11

<=> x = 1

Answer 4

3x(x+5)-(x+2)^2=2x^2+7 

=> 3x^2 + 15x - x^2 - 4x - 4 = 2x^2 + 7

=> 2x^2 + 11x - 4 = 2x^2 + 7

=> 11x = 7 + 4

=> 11x = 11

=> x = 1

Answer 5

\(3x\left(x+5\right)-\left(x+2\right)^2=2x^2+7.\)

\(3x^2+15x-x^2-4x-4=2x^2+7\)

\(2x^2+11x-4=2x^2+7\)

\(11x-4=7\)

\(11x=7+4\)

\(11x=11\)

\(x=1\)

dấu \(\Leftrightarrow\)dùng phải đúng trường hợp chứ nhiều bn làm vậy cho ngầu hả

Answer 6

3.x .( x + 5 ) - ( x + 2)² = 2.x² + 7

<=> 3.x² + 15.x - x²-4.x-4=2.x²+7

<=> 3.x²-2.x²-x² + 15.x - 4.x = 7 + 4

<=>11 .x = 11

<=> x      = 11 : 11

<=> x       = 1