Question

giải phương trình\(\left(x-1\right)\cdot\left(x^2+3x-2\right)-\left(x^3-1\right)=0\)

Answer 1

<=>(x-1)(x²+3x-2) - (x-1)(x²+x+1)=0<=>(x-1)(x²+3x-2-x²-x-1)=0<=>(x-1)(2x-3)=0<=>x-1=0 hoặc 2x-3=0<=>x=1 hoặc x=3/2

VẬY S=1;3/2                :)))))))))))))))))))))))))