\(b,5x+2\left(x-7\right)=35\\ \Leftrightarrow5x+2x-14-35=0\\ \Leftrightarrow7x-49=0\\ \Leftrightarrow7x=49\\ \Leftrightarrow x=7\\ d,đk:x\ne2;x\ne0\\ \dfrac{x+2}{x-2}-\dfrac{1}{x}-\dfrac{2}{x^2-2x}=0\\ \Leftrightarrow\dfrac{x+2}{x-2}-\dfrac{1}{x}-\dfrac{2}{x\left(x-2\right)}=0\\ \Leftrightarrow\dfrac{x\left(x+2\right)-\left(x-2\right)-2}{x\left(x-2\right)}=0\\ \Leftrightarrow x^2+2x-x+2-2=0\\ \Leftrightarrow x^2+x=0\\ \Leftrightarrow x\left(x+1\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=0\left(kot/m\right)\\x=-1\left(t/m\right)\end{matrix}\right.\)
\(5x+2\left(x-7\right)=35\)
\(\Leftrightarrow5x+2x-14=35\)
\(\Leftrightarrow7x-14=35\)
\(\Leftrightarrow7x=49\)
\(\Leftrightarrow x=7\)
\(\text{Vậy phương trình có tập nghiệm là }S=\left\{7\right\}\)
\(\dfrac{x+2}{x-2}-\dfrac{1}{x}-\dfrac{2}{x^2-2x}=0\) \(\text{ĐKXĐ:}x\ne0;x\ne2\)
\(\Leftrightarrow\dfrac{x+2}{x-2}-\dfrac{1}{x}-\dfrac{2}{x\left(x-2\right)}=0\)
\(\Leftrightarrow\dfrac{x\left(x+2\right)}{x\left(x-2\right)}-\dfrac{x-2}{x\left(x-2\right)}-\dfrac{2}{x\left(x-2\right)}=0\)
\(\Rightarrow x^2+2x-x+2-2=0\)
\(\Leftrightarrow x^2+x=0\)
\(\Leftrightarrow x\left(x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\left(\text{loại}\right)\\x=-1\left(\text{nhận}\right)\end{matrix}\right.\)
\(\text{Vậy phương trình có tập nghiệm là }S=\left\{-1\right\}\)