Question

giải phương trình sau:

(x+2)^3-(x-2)^3=12x(x-1)-8

giúp mình với ạ!

 

Answer 1

(x+2)^3-(x-2)^3=12x(x-1)-8

<=>x^3+6x^2+12x+8-x^3+6x^2-12x+8=12x^2-12x-8

<=>12x^2+16=12x^2-12x-8

<=>12x+24=0

<=>x=-24/12=-2

Vậy S={-2}

tick nha các bạn

Answer 2

 

(x+2)^3-(x-2)^3=12x(x-1)-8

<=>x³+6x²+12x+8-x³+6x²-12x+8=12x²-12x-8

<=>12x²+16=12x²-12x-8

<=>12x+24=0

<=>x=-24/12=-2

Vậy S={-2}

Answer 3

(x+2)^3-(x-2)^3=12x(x-1)-8

<=>x^3+6x^2+12x+8-x^3+6x^2-12x+8=12x^2-12x-8

<=>12x^2+16=12x^2-12x-8

<=>12x+24=0

<=>x=-24/12=-2

Vậy S={-2}

Answer 4

(x+2)^3-(x-2)^3=12x(x-1)-8

<=>x^3+6x^2+12x+8-x^3+6x^2-12x+8=12x^2-12x-8

<=>12x^2+16=12x^2-12x-8

<=>12x+24=0

<=>x=-24/12=-2

Vậy S={-2}

k nha các bạn