Question

 

giải phương trình sau:

x^2- 10x+16=0

 

 

Answer 1

`x^2-10x+16=0`

`<=>x^2-8x-2x+16=0`

`<=>x(x-8)-2(x-8)=0`

`<=>(x-8)(x-2)=0`

`<=>[(x-8=0),(x-2=0):}<=>[(x=8),(x=2):}`

Answer 2

\(x^2-2x-8x-16=0\)

--> \(x.\left(x-2\right)-8\left(x-2\right)=0\)

--> \(\left(x-2\right).\left(x-8\right)=0\Leftrightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)

Answer 3

\(x^2-10x+16=0\)

\(\Leftrightarrow x^2-8x-2x+16=0\)

\(\Leftrightarrow x\left(x-8\right)-2\left(x-8\right)=0\)

\(\Leftrightarrow\left(x-8\right)\left(x-2\right)=0\) \(\Leftrightarrow\) \(\left[{}\begin{matrix}x-8=0\\x-2=0\end{matrix}\right.\) \(\Leftrightarrow\) \(\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)