Question

Giải phương trình:  \(\frac{3}{7}x-1-\frac{1}{7}x\left(3x-7\right)=0\)

Answer 1

\(\frac{3}{7}x-1-\frac{3}{7}x^2+x=0\)=> 3x-7-3x² + 7x = 0 => 3x² -10x +7 =0 

=> 3x² -3x-7x +7 =0 => 3x(x-1)-7(x-1)=0 => (3x-7)(x-1)=0 => x=7/3 hoặc x=1 

Answer 2

X = 7/3 hoặc là 1

Answer 3

\(pt\Leftrightarrow\frac{1}{7}\left(3x-7\right)-\frac{1}{7}x\left(3x-7\right)=0\Leftrightarrow\left(\frac{1}{7}-\frac{1}{7}x\right)\left(3x-7\right)=0\)

\(\Leftrightarrow\frac{1}{7}\left(1-x\right)\left(3x-7\right)=0\)

\(\Leftrightarrow\)x=1 hay x =7/3