Ta có: \(\left\{{}\begin{matrix}-x-y=2\\-2x-3y=9\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}-\left(x+y\right)=2\\-\left(2x+3y\right)=9\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x+y=-2\\2x+3y=-9\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=-2-y\\2\cdot\left(-2-y\right)+3y=-9\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-2-y\\-4-2y+3y+9=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=-2-y\\y+5=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-2-y\\y=-5\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=-2-\left(-5\right)\\y=-5\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-2+5=3\\y=-5\end{matrix}\right.\)
Vậy: Hệ phương trình có nghiệm duy nhất là \(\left\{{}\begin{matrix}x=3\\y=-5\end{matrix}\right.\)