\(\left\{{}\begin{matrix}X+44=Y\\\dfrac{120}{X}+\dfrac{11}{30}=\dfrac{120}{Y}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}X=Y-44\\3600Y+11XY=3600X\end{matrix}\right.\)
\(3600Y+11\left(Y-44\right)Y=3600\left(Y-44\right)\\ =11Y^2-484Y+158400 =0\)
\(\Delta'=\left(-242\right)^2-158400.11=-1683836\)
=> DO \(\Delta'>0\) nên pt vô nghiệm