Question

giải hệ phương trình \(\left\{{}\begin{matrix}\text{a}\sqrt{\text{a}^2+b^2}-6\sqrt{a^2+b^2}=7a+b\\\text{b}\text{ }\sqrt{\text{a}^2+b^2}-\sqrt{a^2+b^2}=7b-a\end{matrix}\right.\)

Answer 1

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