\(a,=a^2+2a+1-a^2+2a-1-3a^2+3=-3a^2+4a+3\\ b,=\left[\left(m^3-m+1\right)-\left(m^2-3\right)\right]^2\\ =\left(m^3-m^2-m+4\right)^2\)
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