(2x+1) + (2x+2) + (2x+3) +.....+ (2x+2015) = 0
=> 2015.2x + (1+2+3+...+2015) = 0
=> 4030x + 2031120 = 0
=> 4030x = -2031120
=> x = -504
Đúng 0
Bình luận (0)
Ta có: (2x + 1) + (2x + 2) + (2x + 3) +.....+ (2x + 2015) = 0
<=> (2x + 2x + 2x + ..... + 2x) + (1+2+3+...+2015) = 0
<=> 4030x + 2031120 = 0
=> 4030x = -2031120
=> x = -2031120 : 4030
=> x = -504
Đúng 0
Bình luận (0)