Question

Giải dùm mình câu này luôn ạ cảm ơn nhiều

Answer 1

\(=\dfrac{\sqrt{2}.\sqrt{2}}{\sqrt{2}}+\dfrac{3\sqrt{2}.\left(\sqrt{2}-1\right)}{2-1}-\dfrac{\sqrt{2}}{2}\)

\(=\sqrt{2}+6-3\sqrt{2}-\dfrac{\sqrt{2}}{2}\)

\(=-2\sqrt{2}+6-\dfrac{\sqrt{2}}{2}\)

\(=\dfrac{-4\sqrt{2}+12-\sqrt{2}}{2}\)

\(=\dfrac{12-5\sqrt{2}}{2}\)