\(\left(\dfrac{12}{7}:x-0,5\right)\times\left(\dfrac{2}{5}x-\dfrac{11}{2}\right)=0\\ \Rightarrow\left[{}\begin{matrix}\dfrac{12}{7}:x-0,5=0\\\dfrac{2}{5}x-\dfrac{11}{2}=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}\dfrac{12}{7}:x=\dfrac{1}{2}\\\dfrac{2}{5}x=\dfrac{11}{2}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{12}{7}:\dfrac{1}{2}\\x=\dfrac{11}{2}:\dfrac{2}{5}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{12}{7}\times2\\x=\dfrac{11}{2}\times\dfrac{5}{2}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{24}{7}\\x=\dfrac{55}{4}\end{matrix}\right.\)
Vậy \(x=\dfrac{24}{7};x=\dfrac{55}{4}\)
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