Question

Giải các phương trình nghiệm nguyên: 3x + 19y = 168

Answer 1

Ta có: \(3x+19y=168\)

\(\Rightarrow3x=168-19y\Rightarrow x=56-\dfrac{19y}{3}\)

Để \(x\in Z\Leftrightarrow19y⋮3\Leftrightarrow y⋮3\)

\(\Rightarrow y=3t\left(t\in Z\right)\)

Khi đó \(x=56-19t\)

Vậy \(\left(x;y\right)\in\left\{56-19t;3t\right\}\left(t\in Z\right)\)

Answer 2

3x + 19y = 168

<=> \(\left\{{}\begin{matrix}x=\dfrac{168-19x}{3}\\y=\dfrac{168-3x}{19}\end{matrix}\right.\)

Answer 3

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Answer 4

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