a) \(3x-5\le x+1\)
\(\Leftrightarrow3x-x\le1+5\)
\(\Leftrightarrow2x\le6\)
\(\Leftrightarrow x\le3\)
Vậy.............
b) \(\frac{2x-2}{2}>\frac{2-x+2}{3}\)
\(\Leftrightarrow3\left(2x-2\right)>2\left(2-x+2\right)\)
\(\Leftrightarrow6x-6>4-2x+4\)
\(\Leftrightarrow6x+2x>4+4+6\)
\(\Leftrightarrow8x>14\)
\(\Leftrightarrow x>\frac{7}{4}\)
Vậy..................
a,\(3x-5\le x+1\Leftrightarrow2x\le6\Leftrightarrow x\le3\)
b,\(\frac{2x-2}{3}>2-\frac{x+2}{2}\)
\(\Leftrightarrow2\left(2x-2\right)>12-3\left(x+2\right)\)
\(\Leftrightarrow4x-4>12-3x-6\)
\(\Leftrightarrow7x>10\Leftrightarrow x>\frac{10}{7}\)
đcm đưa cái đề sai như cc lần sau gõ công thức toán cho t