\(\left(x-\frac{1}{4}\right)\div\frac{4}{3}=\frac{1}{2}\)
\(\Leftrightarrow x-\frac{1}{4}=\frac{1}{2}\times\frac{4}{3}\)
\(\Leftrightarrow x-\frac{1}{4}=\frac{4}{6}\)
\(\Leftrightarrow x-\frac{3}{12}=\frac{8}{12}\)
\(\Leftrightarrow x=\frac{8}{12}+\frac{3}{12}\)
\(\Leftrightarrow x=\frac{11}{12}\)
\(\left(X-\frac{1}{4}\right):\frac{4}{3}=\frac{1}{2}\)
\(\Rightarrow X-\frac{1}{4}=\frac{1}{2}.\frac{4}{3}\)
\(\Rightarrow X-\frac{1}{4}=\frac{2}{3}\)
\(\Rightarrow X=\frac{2}{3}+\frac{1}{4}\)
\(\Rightarrow X=\frac{11}{12}\)
\(=>x-\frac{1}{4}=\frac{2}{3}\)
\(=>x=\frac{2}{3}+\frac{1}{4}\)
\(=>x=1\)
(X-\(\frac{1}{4}\));\(\frac{4}{3}\)=\(\frac{1}{2}\)
X-\(\frac{1}{4}\)=\(\frac{1}{2}\)x\(\frac{3}{4}\)
X-\(\frac{1}{4}\)=\(\frac{3}{8}\)
X=\(\frac{3}{8}\)+\(\frac{1}{4}\)
x=\(\frac{5}{8}\)
\(\left(x-\frac{1}{4}\right):\frac{4}{3}=\frac{1}{2}\)
\(\left(x-\frac{1}{4}\right)=\frac{1}{2}.\frac{4}{3}\)
\(\left(x-\frac{1}{4}\right)=\frac{2}{3}\)
\(x=\frac{2}{3}+\frac{1}{4}\)
\(x=\frac{11}{12}\)