\(\left(2x-1\right)^3=-8\)
\(\left(2x-1\right)^3=\left(-2\right)^3\)
\(\Rightarrow2x-1=-2\)
\(2x=\left(-2\right)+1=-1\)
\(x=-\frac{1}{2}\)
(2x - 1)3 = -8 => (2x - 1)3 = (-2)3 => 2x - 1 = 2 => 2x = 3 => x = 3/2
Ta có \(-\sqrt[3]{8}=-2\)
=> 2x-1=-2 => 2x=-2+1=-1
=>x=-1/2
(2x - 1)3 = -8 => (2x - 1)3 = (-2)3 => 2x - 1 = -2 => 2x = -1 => x = -1/2
(2x-1)3= -8
(2x-1)3=(-2)3
2x-1 =-2
2x =-2+1=-1
x =-1:2=-1/2=-0.5
Vậy x =-0,5