ĐKXĐ:x\(\ne\)\(\frac{2}{3}\)
\(\frac{x+\frac{2}{3}}{x-\frac{2}{3}}< 0\)
\(\Leftrightarrow\)(x+2/3) và (x-2/3) \(\ne\)dấu
TH1: x+2/3>0\(\Leftrightarrow\)x>-2/3
x-2/3<0\(\Leftrightarrow\)x<2/3
\(\Rightarrow\)-2/3<x<2/3.
TH2: x+2/3<0\(\Leftrightarrow\)x<-2/3
x-2/3>0\(\Leftrightarrow\)x>2/3
\(\Rightarrow\)x ko tồn tại.
KL: Vậy -2/3<x<2/3
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)
tìm x :
\(\frac{1}{3}x+\frac{2}{5}\left(x-1\right)=0\)
\(3\left(x-\frac{1}{2}\right)-5\left(x-\frac{2}{3}\right)=\frac{3}{2}x\)
Tìm x, biết rằng:
\(\frac{\frac{2}{7}+x+\frac{2}{17}-\frac{2}{293}}{\frac{3}{7}+\frac{3}{5}+\frac{3}{17}-\frac{3}{293}}-\frac{2}{3}=0\)
Tìm x, biết:
a)\(\frac{3}{2}-\frac{2}{7}< \frac{2}{3}x+\frac{3}{4}< \frac{1}{2}+\frac{7}{9}\)
b)\(\left(x-\frac{1}{3}\right).\left(x+\frac{2}{5}\right)>0\)
Tìm x
\(\left(2x+\frac{3}{5}\right)^2-\frac{9}{25}=0\)
\(3\left(3x-\frac{1}{2}\right)^3+\frac{1}{9}=0\)
\(-5\left(x+\frac{1}{5}\right)-\frac{1}{2}\left(x-\frac{2}{3}\right)=\frac{3}{2}x-\frac{5}{6}\)
\(3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=-x+\frac{1}{5}\)
giải nhanh hộ mình với, mai mình nộp rồi
Tìm x, biết:
a)\(\frac{x}{5}\)= \(\frac{2}{3}\)
b)\(\frac{x}{-24}\) = \(\frac{20}{40}\)
c)\(\frac{x+3}{15}\) = \(\frac{1}{3}\)
d)\(\frac{2}{3}.x-\frac{3}{2}.x=\frac{5}{12}\)
e)\(\frac{-2}{3}.x+\frac{1}{5}.x-\frac{3}{10}=0\)
f)\(\frac{-2}{3}-\frac{1}{3}.\left(2.x-5\right)=\frac{3}{2}\)
g)\(\frac{1}{3}.x+\frac{2}{5}\left(x-1\right)=0\)
\(a)\frac{2}{5}:(2x+\frac{3}{4})=\frac{-7}{10}\)
\(b)\frac{x+1}{3}=\frac{2-x}{2}\)
\(c)|x-\frac{3}{5}|.\frac{1}{2}-\frac{1}{5}=0\)
\(^{d)x^2-4x=0}\)
Tìm x giúp mình nha!!!
tìm x :
a)\(x:4\frac{1}{3}=2.5\)
b)\(x:\frac{-3}{5}=\frac{-10}{21}\)
c)\(\frac{2}{3}.x-\frac{1}{2}=\frac{1}{10}\)
d)\(\frac{1}{3}.x+\frac{2}{5}\left(x-1\right)=0\)
e)\(\frac{1}{2}.x+\frac{1}{2}=\frac{5}{2}\)
f)\(\frac{-2}{3}-\frac{1}{3}\left(2x-5\right)=\frac{3}{2}\)
g)\(\left(3x-1\right)\left(-\frac{1}{2}.x+5\right)=0\)
h)\(3\frac{1}{3}+\frac{5}{6}.x=3\frac{1}{2}\)