TN

 \(\frac{x+3}{1995}\)\(\frac{x+1}{1997}\)= -2

 

H24
4 tháng 11 2017 lúc 18:49

Ta có: \(\frac{x+3}{1995}+\frac{x+1}{1997}=-2\)

\(\Leftrightarrow\left(\frac{x+3}{1995}+1\right)+\left(\frac{x+1}{1997}+1\right)=0\)( cộng cả hai vế cho 2)

\(\Leftrightarrow\frac{x+1998}{1995}+\frac{x+1998}{1997}=0\)

\(\Leftrightarrow\left(x+1998\right).\left(\frac{1}{1995}+\frac{1}{1997}\right)=0\)

Mà    \(\frac{1}{1995}+\frac{1}{1997}\ne0\)

\(\Rightarrow x+1998=0\)

\(\Rightarrow x=-1998\)

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