Question

\(\frac{x^2+38x+4}{2x^2+17x+1}+\frac{3x^2-4x-2}{2x^2+17x+1}\)

Answer 1

\(\frac{x^2+38x+4}{2x^2+17x+1}+\frac{3x^2-4x-2}{2x^2+17x+1}=\frac{x^2+38x+4+3x^2-4x-2}{2x^2+17x+1}\)\(=\frac{4x^2+34x+2}{2x^2+17x+1}=\frac{2\left(2x^2+17x+1\right)}{\left(2x^2+17x+1\right)}=2\)

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Answer 2

ko hiểu cho lắm

Answer 3

 =\(\frac{4x^2+34x+2}{2x^2+17x+1}\)

=\(\frac{2\left(2x^2+17x+1\right)}{2x^2+17x+1}\)

=2