\(\frac{x+1}{5}+\frac{x+1}{6}=\frac{x+1}{7}+\frac{x+1}{8}\)
\(\Rightarrow\frac{x+1}{5}+\frac{x+1}{6}-\frac{x+1}{7}-\frac{x+1}{8}=0\)
\(\Rightarrow\left(x+1\right)\cdot\frac{1}{5}+\left(x+1\right)\cdot\frac{1}{6}-\left(x+1\right)\cdot\frac{1}{7}-\left(x+1\right)\cdot\frac{1}{8}=0\)
\(\Rightarrow\left(x+1\right)\cdot\left(\frac{1}{5}+\frac{1}{6}-\frac{1}{7}-\frac{1}{8}\right)=0\)
\(\Rightarrow\left(x+1\right)\cdot\frac{293}{840}=0\)
\(\Rightarrow x+1=0\)
\(\Rightarrow x=-1\)
nếu thấy đúng thì k cho mh nha
\(\frac{x+1}{5}+\frac{x+1}{6}=\frac{x+1}{7}+\frac{x+1}{8}\)
\(\Rightarrow\frac{x+1}{5}+\frac{x+1}{6}-\frac{x+1}{7}-\frac{x+1}{8}=0\)
\(\Rightarrow\left(x+1\right)\cdot\left(\frac{1}{5}+\frac{1}{6}-\frac{1}{7}-\frac{1}{8}\right)=0\)
\(\Leftrightarrow x+1=0\)
\(\Leftrightarrow x=-1\)
k nha