Question

\(\frac{x+1}{2}=\frac{8}{x+1}\)

tìm x 

Answer 1

Ta có; vậy 

=> (x+1)² = 2 x 8 

=> (x + 1)² = 16

=> x + 1 = 4

=> x = 3

Answer 2

Bài này mình biết :

\(\frac{x+1}{2}=\frac{8}{x+1}\)

\(=\left(x+1\right)^2=8\times2\)

\(=\left(x+1\right)^2=16\)

\(=\left(x+1\right)=\sqrt{16}\)

\(=\left(x+1\right)=4\)

\(=x=4-1\)

\(=x=3\)

Answer 3

\(\frac{x+1}{2}=\frac{8}{x+1}\Leftrightarrow\left(x+1\right)^2=16=4^2\)

\(\Rightarrow x+1=4\)hoặc \(x+1=-4\)

\(\Rightarrow x=3\) hoặc \(x=-5\)

Answer 4

   \(\frac{x+1}{2}=\frac{8}{x+1}\)

=  \(\left(x+1\right)^2=8x2\)

= \(\left(x+1\right)^2=16\)

= \(x+1=\sqrt{16}\)

= \(x+1=4\)

=  \(x=4-1\)

= \(x=3\)