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\(\frac{x-10}{30}+\frac{x-14}{43}+\frac{x-5}{95}+\frac{x-148}{8}=0\)0
giải chi tiết
Tìm x, biết:frac{3}{left(x+2right)left(x+5right)}+frac{5}{left(x+5right)left(x+10right)}+frac{7}{left(x+10right)left(x+17right)}frac{x}{left(x+2right)left(x+17right)}left(xnotin-2;-5;-10;-17right)frac{2}{left(x-1right)left(x-3right)}+frac{5}{left(x-3right)left(x-8right)}+frac{12}{left(x-8right)left(x-20right)}-frac{1}{x-20}-frac{3}{4}Với xnotin1;3;8;20frac{x+1}{10}+frac{2+1}{11}frac{x+1}{12}frac{x+1}{13}+frac{x+1}{14}frac{x-10}{30}+frac{x-14}{43}+frac{x-5}{95}+frac{x-148}{8}0
Đọc tiếp
Tìm x, biết:
\(\frac{3}{\left(x+2\right)\left(x+5\right)}+\frac{5}{\left(x+5\right)\left(x+10\right)}+\frac{7}{\left(x+10\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\left(x\notin-2;-5;-10;-17\right)\)
\(\frac{2}{\left(x-1\right)\left(x-3\right)}+\frac{5}{\left(x-3\right)\left(x-8\right)}+\frac{12}{\left(x-8\right)\left(x-20\right)}-\frac{1}{x-20}=-\frac{3}{4}\)
Với \(x\notin1;3;8;20\)
\(\frac{x+1}{10}+\frac{2+1}{11}\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
\(\frac{x-10}{30}+\frac{x-14}{43}+\frac{x-5}{95}+\frac{x-148}{8}=0\)
\(\frac{x+5}{95}+\frac{x+10}{90}+\frac{x+15}{85}+\frac{x+20}{80}=-4\)
\(\frac{x-1}{99}+\frac{x-2}{98}+\frac{x-5}{95}=3+\frac{1}{99}+\frac{1}{98}+\frac{1}{95}\)\(\frac{1}{95}\)
Bài 1 : Tìm x1) frac{x-1}{10} + frac{x-1}{11}+frac{x-1}{12}-frac{x-1}{13} 02 ) frac{x-1}{99}+frac{x-2}{98}+frac{x-5}{95} 3 + frac{1}{99}+frac{1}{98}+frac{1}{95}
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Bài 1 : Tìm x
1) \(\frac{x-1}{10}\) + \(\frac{x-1}{11}\)+\(\frac{x-1}{12}\)-\(\frac{x-1}{13}\)= 0
2 ) \(\frac{x-1}{99}\)+\(\frac{x-2}{98}\)+\(\frac{x-5}{95}\)= 3 + \(\frac{1}{99}\)+\(\frac{1}{98}\)+\(\frac{1}{95}\)
H24
23 tháng 7 2023 lúc 11:26
tìm x biết:x-10/30+x-5/95=14-x/43+148-x/8
frac{x+1}{10}+frac{x+1}{11}+frac{x+1}{12}frac{x+1}{13}+frac{x+1}{14}frac{x+4}{2006}+frac{x+3}{2007}frac{x+2}{2008}+frac{x+1}{2009}frac{x+1945}{45}+frac{x+1954}{54}frac{x+1975}{75}+frac{x+1969}{69}frac{x-99}{5}+frac{x-97}{7}frac{x-95}{9}+frac{x-93}{11}frac{x+2008}{10}+frac{x+2010}{9}frac{x+2012}{8}+frac{x+2014}{7}
Đọc tiếp
\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)\(\frac{x+4}{2006}+\frac{x+3}{2007}=\frac{x+2}{2008}+\frac{x+1}{2009}\)\(\frac{x+1945}{45}+\frac{x+1954}{54}=\frac{x+1975}{75}+\frac{x+1969}{69}\)\(\frac{x-99}{5}+\frac{x-97}{7}=\frac{x-95}{9}+\frac{x-93}{11}\)\(\frac{x+2008}{10}+\frac{x+2010}{9}=\frac{x+2012}{8}+\frac{x+2014}{7}\)
\(Bài1:x+y=\frac{1}{2},y+z=\frac{1}{3},z+x=\frac{1}{4}\)
\(Bai2:\frac{x-1}{99}+\frac{x-2}{98}+\frac{x-5}{95}=3+\frac{1}{99}+\frac{1}{98}+\frac{1}{95}\)
1. Chứng minh :a) 10^28 + 8 chia hết cho 72b) 481^n + 1999^1999 chia hết cho 102. Tìm x :a)frac{x+29}{31}- frac{x+27}{33} frac{x+17}{43}- frac{x+15}{45}b) frac{1909-x}{91}+ frac{1907-x}{93}+frac{1905-x}{95}+ frac{1903-x}{97}+4 0
Đọc tiếp
1. Chứng minh :
a) 10^28 + 8 chia hết cho 72
b) 481^n + 1999^1999 chia hết cho 10
2. Tìm x :
a)\(\frac{x+29}{31}\)- \(\frac{x+27}{33}\)= \(\frac{x+17}{43}\)- \(\frac{x+15}{45}\)
b) \(\frac{1909-x}{91}\)+ \(\frac{1907-x}{93}\)+\(\frac{1905-x}{95}\)+ \(\frac{1903-x}{97}\)+4 = 0