\(\Rightarrow\frac{x-100}{24}-1+\frac{x-98}{26}-1+\frac{x-96}{28}-1=3-1-1-1=0\)
\(\Rightarrow\frac{x-124}{24}+\frac{x-124}{26}+\frac{x-124}{28}=0\)
\(\Rightarrow\left(x-124\right)\left(\frac{1}{24}+\frac{1}{26}+\frac{1}{28}\right)=0\)
\(\Rightarrow x-124=0\) ( vì 1/24 + 1/26 + 1/28 khác 0)
=> x = 124
Tìm x:
a) \(\frac{x+1}{2011}+\frac{x+1}{2012}=\frac{x+1}{2013}+\frac{x+1}{2014}\)
b)\(\frac{x-100}{24}+\frac{x-98}{26}+\frac{x-96}{28}=3\)
c)\(2.\left(x-\frac{1}{3}\right)-5.\left(x-\frac{1}{4}\right)=4x\)
HELP ME !!!! NHANH NHÉ MIK CẦN GẤP LẮM THANKS CÁC BN IU NHÌU
Tìm x:
a) 100 - 7 . (x - 5) = 58
b) \(x+\frac{1}{3}=\frac{7}{26}.\frac{13}{6}\)
c) \(\left(\frac{1}{2.5}+\frac{1}{5.8}+\frac{1}{8.11}+..........+\frac{1}{97.100}\right)x=\frac{98}{100}\)
Tính:\(\frac{x+1}{99}+\frac{x+2}{98}+\frac{x+3}{97}+\frac{x+4}{96}=-4\)
\(\frac{x+1}{99}+\frac{x+2}{98}+\frac{x+3}{97}+\frac{x+4}{96}=-4\)
tim x
Tìm x biết :
\(\frac{x+1}{99}+\frac{x+2}{98}+\frac{x+3}{97}+\frac{x+4}{96}=-4\)
\(\frac{x+1}{99}+\frac{x+2}{98}+\frac{x+3}{97}+\frac{x+4}{96}=0\)
\(\frac{x+1}{99}+\frac{x+2}{98}+\frac{x+3}{97}+\frac{x+4}{96}=-4\)hãy tìm x
\(\frac{x+1}{99}+\frac{x+2}{98}+\frac{x+3}{97}+\frac{x+4}{96}=-4\)hãy tìm x
Tìm x , biết :
\(\frac{x+1}{99}+\frac{x+3}{97}+\frac{x+5}{95}=\frac{x+2}{98}+\frac{x+4}{96}+\frac{x+6}{94}\)