Question

\(\frac{\sqrt{96}+\sqrt{300}-\sqrt{54}}{\sqrt{6}}\)

giúp mk với

 

Answer 1

=1+5\(\sqrt{2}\)

Answer 2

diễn giải ra hộ mk với

Answer 3

\(\frac{\sqrt{96}+\sqrt{300}-\sqrt{54}}{\sqrt{6}}\)

\(=\frac{\sqrt{16.6}+\sqrt{3.100}-\sqrt{9.6}}{\sqrt{6}}\)

\(=\frac{\sqrt{4^2.6}+\sqrt{10^2.3}-\sqrt{3^2.6}}{\sqrt{6}}\)

\(=\frac{4\sqrt{6}+10\sqrt{3}-3\sqrt{6}}{\sqrt{6}}\)

\(=\frac{\sqrt{6}+10\sqrt{3}}{\sqrt{6}}\)

\(=10\sqrt{3}\)

K nha 

Answer 4

\(\sqrt{96}=\sqrt{16.6}=4\sqrt{6}\)

\(\sqrt{300}=\sqrt{25.2.6}=5.\sqrt{2}\sqrt{6}\)

\(\sqrt{54}=\sqrt{9.6}=3\sqrt{6}\)

\(\Rightarrow\)Biểu thức:

\(4\sqrt{6}+5\sqrt{2}\sqrt{6}-3\sqrt{6}\)/\(\sqrt{6}\)

=\(\left(4+5\sqrt{2}-3\right)\sqrt{6}\)/ \(\sqrt{6}\)

=\(4+5\sqrt{2}-3\)

Answer 5

thanks