Question

\(\frac{a}{b}\)* 4 + \(\frac{1}{6}\)=\(\frac{17}{6}\)

Giải giúp mình nhé

 

Answer 1

\(\frac{a}{b}.4+\frac{1}{6}=\frac{17}{6}\)

\(\frac{a}{b}.4\)          \(=\frac{17}{6}-\frac{1}{6}\)

\(\frac{a}{b}.4\)           \(=\frac{8}{3}\)

                      \(\frac{a}{b}=\frac{8}{3}:4\)

                      \(\frac{a}{b}=\frac{2}{3}\)

Answer 2

\(\frac{a}{b}.4=\frac{17}{6}-\frac{1}{6}\)

\(\frac{a}{b}.4=\frac{16}{6}\)

\(\frac{a}{b}=\frac{16}{6}:4\)

\(\frac{a}{b}=\frac{16}{6}.\frac{1}{4}=\frac{16}{6.4}=\frac{2}{3}\)