Question

\(\frac{7}{9}.\frac{3}{8}+\frac{7}{9}.\frac{5}{8}-\frac{1}{3}\)

Answer 1

\(\frac{7}{9}.\frac{3}{8}+\frac{7}{9}.\frac{5}{8}-\frac{1}{3}\)

\(=\frac{7}{9}.\left(\frac{3}{8}+\frac{5}{8}\right)-\frac{1}{3}\)

\(=\frac{7}{9}.1-\frac{1}{3}\)

\(=\frac{7}{9}-\frac{1}{3}\)

\(=\frac{4}{9}\)

Answer 2

7/9( 3/8+3/8) - 1/3 = 7/9.1-1/3 = 4/9

Answer 3

\(=\frac{7}{9}.\left(\frac{3}{8}+\frac{5}{8}\right)-\frac{1}{3}=\frac{7}{9}.1-\frac{1}{3}=\frac{7}{9}-\frac{3}{9}=\frac{4}{9}\)

Answer 4

\(\frac{7}{9}.\frac{3}{8}+\frac{7}{9}.\frac{5}{8}-\frac{1}{3}\)

\(=\frac{7}{9}.\left(\frac{3}{8}+\frac{5}{8}\right)-\frac{1}{3}\)

\(=\frac{7}{9}.1-\frac{1}{3}\)

\(=\frac{7}{9}-\frac{1}{3}\)

\(=\frac{4}{9}\)