Question

 

\(\frac{4^9.9^4-10.6^9}{2^{10}.3^8+6^8-28}\)

giúp mk đi mơn các bạn nhìu

Answer 1

\(=\frac{\left(2^2\right)^9.\left(3^2\right)^4-2.5.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8-28}\)

\(=\frac{2^{18}.3^8-2.5.2^9.3^9}{2^{10}3^8+2^8.3^8-28}\)

\(=\frac{2^{18}.3^8-2^{10}.3^9.5}{2^8.3^8.\left(2^2+1\right)-28}\)

\(=\frac{2^{10}.3^8.\left(2^8-3.5\right)}{2^8.3^8.5-28}\)

\(=\frac{2^2.\left(2^8-3.5\right)}{5-28}\)

\(=\frac{2.\left(256-15\right)}{-23}\)

\(=\frac{-482}{23}\)