Tính
\(\frac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}\)
Tính A, biết:
\(A=\frac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}\)
\(\frac{4^6\cdot9^5\cdot6^9+120}{8^4\cdot3^{12}-6^{11}}\)
\(\frac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}\)Tinh gia tri bieu thuc
giai gium minh nha
Help me:
Tính:
( 2-1 + 3-1 ) : ( 2-1 - 3-1 ) + ( 2-1 : 20 ) :23
\(\frac{\left(\frac{2}{5}\right)^7\cdot5^7+\left(\frac{9}{4}\right)^3:\left(\frac{3}{16}\right)^3}{2^7\cdot5^2+512}\)
\(\frac{4^6\cdot9^5+6^9\cdot120}{^{8^4\cdot3^{12}-6^{11}}}\)
\(\frac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}\)
Giá trị của biểu thức \(\frac{7\cdot\left(4^6\cdot9^5+6^9\cdot120\right)}{-8^4\cdot3^{12}-6^{11}}\) =?
\(\dfrac{4^6\cdot9^5+6^9\cdot120}{-8^4\cdot3^{12}+6^{11}}\)
RÚT GỌN
a/\(\frac{9^4\cdot27^5\cdot3^6\cdot3^4}{3^8\cdot81^4\cdot234\cdot8^6}\)
b/\(N=\frac{4^6\cdot9^5+6^6\cdot120}{8^4-3^{12}-6}\)
\(\frac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^2-6^{11}}\)
. là nhân nhé . Đề bài thính hợp lý
nhanh gọn lẹ cho mik nge
