\(\frac{3}{1.2}+\frac{3}{2.3}+........+\frac{3}{99.100}\)
\(=3\left(\frac{1}{1.2}+\frac{1}{2.3}+.....+\frac{1}{99.100}\right)\)
\(=3\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+.........+\frac{1}{99}-\frac{1}{100}\right)\)
\(=3\left(1-\frac{1}{100}\right)\)
\(=\frac{3.99}{100}=\frac{297}{100}\)