`(2^6 . 3^3 . 121^2 . 5 - 2^4 . 3^3 . 11^4)/(3^2 . 5^4 . 11^4 - 2^2 . 3^2 . 5^2 . 11^5)`
`= (2^6 . 3^3 . 11^4 . 5 - 2^4 . 3^3 . 11^4)/(3^2 . 5^4 . 11^4 - 2^2 . 3^2 . 5^2 . 11^5)`
`= (2^4 . 3^3 . 11^4 (2^2 . 5 - 1))/(3^2 . 5^2 . 11^4 (5^2 - 2^2 . 11))`
`= (2^4 . 3 . (20 - 1))/( 25 . (25 - 44))`
`= (2^4 . 3 . 19)/(25 . (-19))`
`= -(16 . 3 )/25 `
`= -48/25 `
\(\frac{2^3\cdot3^5\cdot5^7}{2^4\cdot3^4\cdot5^8}\)
tính hợp lí :
B=\(\frac{1\cdot4}{2\cdot3}+\frac{2\cdot5}{3\cdot4}+\frac{3\cdot6}{4\cdot5}+.....+\frac{98\cdot101}{99\cdot100}\)
Tính nhanh
A=\(\frac{1\cdot5\cdot6+2\cdot10\cdot12+3\cdot15\cdot18+4\cdot20\cdot24+5\cdot25\cdot30}{1\cdot3\cdot5+2\cdot6\cdot10+3\cdot9\cdot15+4\cdot12\cdot20+5\cdot15\cdot25}\)
Help me:
Tính:
( 2-1 + 3-1 ) : ( 2-1 - 3-1 ) + ( 2-1 : 20 ) :23
\(\frac{\left(\frac{2}{5}\right)^7\cdot5^7+\left(\frac{9}{4}\right)^3:\left(\frac{3}{16}\right)^3}{2^7\cdot5^2+512}\)
\(\frac{4^6\cdot9^5+6^9\cdot120}{^{8^4\cdot3^{12}-6^{11}}}\)
\(\frac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}\)
\(\frac{2^2}{1\cdot3}\cdot\frac{3^2}{2\cdot4}\cdot\frac{4^2}{3\cdot5}...\frac{50^2}{49\cdot51}=?\)
\(\frac{2^2}{1\cdot3}\cdot\frac{3^2}{2\cdot4}\cdot\frac{4^2}{3\cdot5}...\frac{50^2}{49\cdot51}=?\)
\(A=\frac{1.5\cdot6+2\cdot10\cdot12+3\cdot15\cdot18+4\cdot20\cdot24+5\cdot25\cdot30}{1\cdot3\cdot5+2\cdot6\cdot10+3\cdot9\cdot15+4\cdot12\cdot20+5\cdot15\cdot25}\)
cho \(B=\frac{2^2}{1\cdot3}+\frac{3^2}{2\cdot4}+\frac{4^2}{3\cdot5}+...+\frac{99^2}{98\cdot100}\). Tìm phần nguyên của B
\(\frac{1^2}{1\cdot2}\cdot\frac{2^2}{2\cdot3}\cdot\frac{3^2}{3\cdot4}\cdot\cdot\cdot\cdot\frac{10^2}{10\cdot11}\)
\(C=\left(1-\frac{2}{2\cdot3}\right)\cdot\left(1-\frac{2}{3\cdot4}\right)\cdot\left(1-\frac{2}{4\cdot5}\right)\cdot....\cdot\left(1-\frac{2}{99\cdot100}\right)\)
