Dễ thôi mà
\(\frac{25\times4-0,5\times40\times5\times0,2\times20\times0,25}{1+2+4+8+...+128+256}\)\(=\frac{100-\left(0,5\times20\right)\times\left(40\times0,25\right)\times\left(5\times0,2\right)}{1+2+4+8+...+128+256}\)
\(=\frac{100-10\times10\times1}{1+2+4+8+...+128+256}\)\(=\frac{100-100}{1+2+4+8+...+128+256}\)\(=\frac{0}{1+2+4+8+...+128+256}\)= 0
Chúc e học tốt!
giúp mình nha ai nhanh mình tick và kb
Tính nhanh;
b)25x4-0,5x40x5x0,2x20x0,25/1+2+4+8.......+128+256
b =\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{6}...+\frac{1}{128}+\frac{1}{256}\)
\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}+\frac{1}{256}\)
\(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}+\frac{1}{256}\)
Tính : \(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}+\frac{1}{256}\)
tính bằng cách thuận tiện : \(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}...+\frac{1}{128}+\frac{1}{256}\)
\(\frac{25×4-0.5×40×5×0.2×20×0.25}{1+2+4+8...+128+256}\)
\(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}+\frac{1}{256}+\frac{1}{512}\)
Tính :
B = \(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+......+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}+\frac{1}{256}\)