(253+1)x399-145/254+399x253
=253x399+(399-145)/254+399x253
=253x399+254/254+399x253
=1
Ta có:
\(\frac{254X399-145}{254+399X253}\)
\(=\frac{\left(253+1\right)X399-154}{254+399X253}\)
\(=\frac{253X399+399-154}{254+399X253}\)
\(=\frac{253X399+254}{253X399+254}\)
\(=1\)